Consider the following reaction:
$Phenol$ $\xrightarrow{Zn\,dust} X$ $\xrightarrow[{Anhyd.\,AlCl_3}]{CH_3Cl} Y$ $\xrightarrow{Alkaline\,KMnO_4} Z$
The product $Z$ is:

The major product in Reimer-Tiemann reaction is $X$. The reactants are $Y$ and $Z$. $X$,$Y$ and $Z$ are respectively.

Which of the following conversions represents the Fries rearrangement?

Which among the following is obtained as a product when phenol is treated with $NaOH$ and $CO_2$ followed by acid hydrolysis?

When phenol is heated with zinc dust,it forms product $X$. What is the product $X$?

$A$ solution of phenol in chloroform when treated with aqueous $NaOH$ gives compound $P$ as a major product. The mass percentage of carbon in $P$ is $..............$ (to the nearest integer)
(Atomic mass : $C = 12$; $H = 1$; $O = 16$)